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1.080=2x^2+10x-64
We move all terms to the left:
1.080-(2x^2+10x-64)=0
We add all the numbers together, and all the variables
-(2x^2+10x-64)+1.08=0
We get rid of parentheses
-2x^2-10x+64+1.08=0
We add all the numbers together, and all the variables
-2x^2-10x+65.08=0
a = -2; b = -10; c = +65.08;
Δ = b2-4ac
Δ = -102-4·(-2)·65.08
Δ = 620.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-\sqrt{620.64}}{2*-2}=\frac{10-\sqrt{620.64}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+\sqrt{620.64}}{2*-2}=\frac{10+\sqrt{620.64}}{-4} $
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